PHYSICS CLASS: WORK ENERGY AND POWER
Work could be defined as the product of force and distance
moved in the direction of the force. If a force “F” moves a body a distance “S”
in the direction of the force the work one is given by
w = fxs
The sknit of work is joule
Work = force x displacement
(joules) = newtons x metres
WORK DONE IN A FIELD
A typical example of work done in a force field is the
grantational field, to lift up a body under gravity e.g. lifting up a bucket of
water; a force must be applied to overcome the weight of the body. The
magnitude of this work done is
Force x distance
Mg x h
Work done = mgh
Where m = mass of the body (kg)
g = acceleration due to gravity
h = height
This also applies when a body falls from a high the work
done = mgh
Simplified 21 if an engine of force 200Âľ pulls a train 100m
what is the work done by the engine.
Solution
Work done = f x s
=
200 x 100
=
20,000
Simplified 22 A body of mass ran up a flight of 31 steps,
each 15cm high calculate the work by the body (take g = 10m5-2)
Solution
Mass = 70kg
S = 15cm convert to metres = 0.15m
This work is done due to gravity the
workdone =mgh
h = 31steps x 0.15
h = 4.65
w = 70x10x4.65
W = 3255
Simplified 23 the work done when an object is lifted through
a vertical distance of 300cm is 450. Find the mass of the object.
Solution
Workdone = force x distance
W = mg x h
M =?, w = 450, h = 300cm = 3m
450 = mx10x3
450 = 30m
M = 450 = 15kg
30
CONCEPT OF ENERGY
Energy is defined as the capacity or ability to do work,
energy is a scalar quantity and the 5.1 unit.
Joules
FORMS OF ENERGY
Solar
energy
Nuclear
energy
Chemical
energy
Heat
energy
Sound
energy
Light
energy
Mechanical
energy
Electrical
energy etc
MECHANICAL ENERGY
The two forms of mechanical energy we have are
Potential
energy
Kinetic
energy
POTENTIAL ENERGY:
This is defined as the energy possessed by an object by virtue of its position.
Potential energy has the same formula as workdone.
P. E = mgh
This type of potential energy is called grantational energy
which is a measure of the amount of workdone in raising a body to its position.
However the potential energy possessed or stored by springs,
elastic strings when stretched to a certain distance “e” is given by the
equation.
Workdone = average force x extension.
= ½ fe
KINETIC ENERGY:
This is energy which a body has by virtue of its motion.
K.E = 1/2MV2
Where m = mass of an object in kg
V = velocity in m51
NOTE (1) K. E =
PE, K.E + P.E = constant
(2) Work, potential energy and kinetic energy are all
related. The workdone of a given boy is either equal to the kinetic energy
possessed by the body or it is equal to its potential energy
Simplified 24 an object of mass 5kg is moving at a constant
velocity of 50m51 calculate its kinetic energy
Solution
K. E = ½ mv2
K.E = ½ x 5 x (50)2
K.E = ½ x 5x2,500 = 6,250
Simplified 25 an object of mass 4kg at 5m51 was brought to
rest over a distance of 2.8m find the magnitude of the force that brought the
object to rest.
Solution
Workdone = force x distance
Workdone =?
F = ?
D = 2.8
But K.E = workdone
K.E = ½ mv2
M = 4kg
V = 5m51
K. E = ½ x (4) x (5)2 = 50J
K. E = work done byt K.E = 50
50 = f x d
50 = fx2.8
50 = F f = 17.9Âľ
2.8
Simplified 26 A body of mass 5kg falls from a height of 10m
above the ground. What is the kinetic energy of the body just before it strikes
the ground (neglect energy lost and take g = 10m52)
Solution
M = 50kg
H = 10m
V = ?
From equation of motion v2 = u2 x 2gh
V2 = 0x2x10x10
V2 = 200
K.E = ½ MV2
= ½ x 5x200
= 500
Simplified 27 A stationary sledge of mass kg is acted on by
a force of 8N for 5seconds calculate its kinetic energy.
Solution
K.E = 1/2MV2 m = 4kg, f = 8Âľ, = 5seconds from equations of motion
V = u +a ……… (i)
From newton’s first law of motion
F = ma a = f/m = 8/4 = 2m52
But a = 2m52 in equation (1)
v = 0 x 2 x 5 = 10m51
2
CONCEPT OF POWER
Power is defined as the rate of doing work (The rate of
converting energy). Or power is workdone per time taken.
Average power = workdone or force x
distance
time taken time taken
For power = force x velocity
Also f = mg
Where P = power in waste or J51
F = force in Newton (Âľ)
S = distance in metres (m)
H = height in metres (m)
Simplified 28 A machines lifts a load of weight 2500Âľ
through a vertical distance of 3m in 1.5seconds what is the power of the
machine.
Solution
Power = workdone
Time
But workdone = force x distance
= 2500 x 3 = 7500
Simplified 29 A cranes lift a load of weight 4,500Âľ through
a distance of 15m in 10seconds. What is the power of the crane in
Watt
kw
horse power
Solution
Power = force x distance
Time
= 4,500 x 15 = 6750w
10
(b) 1kw = 1000
6750watt = 6750 = 6.75kw
1000
1 horse power = 746watt
6750watt = 6750 = 9lip
746
WORK ENERGY RESOURCES
They word energy resources are classified into
Renewable Energy
Solar (b)wind (c) water (d) biomass
(2) Non-renewable
(a) Nuclear (b) petroleum and natural gas
EXERCISE
A bullet of mass 0.05kg has a speed of 400m51, what
is its kinetic energy if it strikes a wall whose average resisting force is
10,000 calculate the distance penetrated
Ans 400J, 0.4m
No comments:
We Love Comments, Please Comment Below